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Oct 28, 2009 at 16:03 comment added Anton Geraschenko I missed that in the comments to your answer. It seems like taking isomorphism classes in Hom(BG,BH) is destroying more information than I'd like. I'll think about this some more later today and see if I can edit this answer into a description of the category Hom(BG,BH).
Oct 28, 2009 at 7:12 comment added Bhargav I believe your description of Hom(BG,BH) if H is commutative, but not generally. As Reid and I discussed above, even in the usual topological case (i.e., S contractible), pi_0(Map(BG,BH)) = GroupHom(G,H)/conjugation...
Oct 28, 2009 at 5:09 history answered Anton Geraschenko CC BY-SA 2.5