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May 24, 2018 at 14:09 comment added Junior Soares Can you explain me better why $\theta$ has to be necessarily periodic?
May 17, 2018 at 1:03 comment added Tim Carson When you said $\theta: (-\pi, \pi)^3 \to \mathbb{R}_+$ you seemed to be implicitly identifying $\mathbb{T}$ with $[-\pi, \pi]/(-\pi \sim \pi)$. With that identification we can say $(-\pi, \pi)^3 \subset \mathbb{T}^3$.
May 15, 2018 at 12:04 comment added Junior Soares To me there is some issues like that: How may I extends $\theta$ to $\mathbb{T}^3$ if $(\pi, \pi)^3 \not \subset \mathbb{T}^3$?
May 15, 2018 at 12:00 comment added Junior Soares Let me know if I understand. Are you saying that would be much more aproprieted if it were so: Let $M = \mathbb{T}^2 \times (-\pi , \pi)$ be a manifold with the metric: $$g = r^2 dx^2 + (R + r.cos(x))^2 dy^2 + \theta(x,y,z)^2dz^2$$ and $\theta: (-\pi, \pi)^3 \to \mathbb{R_+}$ so $g$ extends to a metric in $\mathbb{T}^3$ if and only if $g$ extends to a periodic function on $\mathbb{T}^3$ such that $$ \int_{-\pi}^{\pi}\theta(x,y,z)dz < \infty$$ where $A = (-\pi, \pi)^3 $?
May 7, 2018 at 22:33 history answered Tim Carson CC BY-SA 4.0