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May 2, 2018 at 12:32 history closed Pietro Majer
Mikhail Katz
Piotr Hajlasz
Ben McKay
Alexey Ustinov
Not suitable for this site
S May 2, 2018 at 5:32 history edited András Bátkai
higher level tag added
S May 2, 2018 at 5:32 history suggested Ali Taghavi
I add a tag.
May 2, 2018 at 5:09 review Suggested edits
S May 2, 2018 at 5:32
May 1, 2018 at 23:56 answer added Iosif Pinelis timeline score: 2
May 1, 2018 at 15:16 comment added Noam D. Elkies As noted already, the asymptotics are easy for positive $z$. Negative or complex $z$ are more interesting but the Bessel-function connection leads to very accurate answers.
May 1, 2018 at 15:07 history edited j.c. CC BY-SA 3.0
add expression to title
May 1, 2018 at 14:46 answer added Ryan O'Donnell timeline score: 6
May 1, 2018 at 14:41 vote accept Shivin Srivastava
May 1, 2018 at 13:00 review Close votes
May 2, 2018 at 7:30
May 1, 2018 at 12:50 answer added Iosif Pinelis timeline score: 4
May 1, 2018 at 9:58 comment added Vincent A little bit more info on the function Carlo Beenakker is referring to can be found at Wikipedia: en.wikipedia.org/wiki/…
May 1, 2018 at 9:39 comment added Carlo Beenakker yes, there is a closed form: $\sum_{k=0}^\infty x^k(k!)^{-2}=I_0(2\sqrt x)$
May 1, 2018 at 9:24 history asked Shivin Srivastava CC BY-SA 3.0