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Apr 23, 2018 at 15:00 vote accept Vikram Saraph
Apr 23, 2018 at 14:39 answer added Chris Schommer-Pries timeline score: 7
Apr 23, 2018 at 13:57 history edited Vikram Saraph CC BY-SA 3.0
added 74 characters in body
Apr 23, 2018 at 13:34 comment added Vikram Saraph @erz could you say a bit more about why exactly the alexander horned sphere shows that $\mathbb{R}^3$ would not be $2$-arcwise connected? Which embedding of $S^2$ is it exactly that fails to extend to $D^3$? I know that the horned sphere is a kind of pathological embedding of the 2-sphere in $\mathbb{R}^3$, but doesn't it still extend to the $3$-ball?
Apr 23, 2018 at 13:32 comment added Vikram Saraph @JeanDuchon I added a definition of $n$-connected.
Apr 23, 2018 at 13:31 history edited Vikram Saraph CC BY-SA 3.0
added definition of n-connected
Apr 23, 2018 at 9:46 comment added Jean Duchon What is $n$-connectedness? If you give a definition for path-connected, I think you should give a definition for this lesser known concept.
Apr 23, 2018 at 5:34 comment added erz If I understand the question correctly, then even such a nice space as $\mathbb{R}^3$ fails to be 2-arcvise connected, because of stuff like a horned sphere.
Apr 22, 2018 at 22:52 review Close votes
Apr 25, 2018 at 5:58
Apr 22, 2018 at 22:26 review First posts
Apr 22, 2018 at 22:36
Apr 22, 2018 at 22:23 history asked Vikram Saraph CC BY-SA 3.0