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Jun 11, 2019 at 0:38 answer added Tim Campion timeline score: 7
Apr 19, 2018 at 2:28 comment added Simon Henry Right, it cannot be comonadic simply because $\Sigma^{\infty}$ is not conservative. so together with Blomquist & Harper results I think this answer my question. thanks
Apr 18, 2018 at 22:07 history edited David White CC BY-SA 3.0
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Apr 18, 2018 at 19:10 comment added Tim Campion With the 1-connected restriction, I think comonadicity is a result of Blomquist and Harper.
Apr 18, 2018 at 18:51 comment added Dylan Wilson whoops- made a silly comment then edited it, but: You need to at least restrict to something like simply connected spaces to have hope, otherwise equivalences are not detected stably
Apr 18, 2018 at 18:49 comment added Dylan Wilson Something like this is true rationally, since unstable rational homotopy types are some extra structure on a rational vector space. More generally, there is an analogous statement "v_n-periodicially". Here are two references: www3.nd.edu/~mbehren1/papers/BKTAQ8.pdf, arxiv.org/pdf/1803.06325v1.pdf
Apr 18, 2018 at 18:41 history asked Simon Henry CC BY-SA 3.0