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Apr 27, 2018 at 7:30 vote accept Gory
Apr 18, 2018 at 15:18 history edited YCor
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Apr 18, 2018 at 14:46 answer added Kimball timeline score: 2
Apr 18, 2018 at 14:22 comment added Gory @SubhajitJana yes however this gives the reverse inclusion, isn't it? I would like to get a support included in a congruence subgroup and your argument provides a congruence subgroup included in it (since it is a basis of neighborhood).
Apr 18, 2018 at 14:20 comment added Gory @Kimball Yes this is the case.
Apr 18, 2018 at 12:45 comment added Kimball $G$ means what? $D^\times(F_v)$ for a ramified nonarchimedean $v$?
Apr 18, 2018 at 10:44 comment added Subhajit Jana For your $x$ we have $f(1)\neq 0$. Because of continuity there exists an open ball around $1$ which is contained in the support of $f$.
Apr 18, 2018 at 7:25 history asked Gory CC BY-SA 3.0