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when toggle format what by license comment
Apr 19, 2018 at 1:06 comment added j.c. @BrendanMcKay Thanks! I'll see if I can work it out when I have some time.
Apr 19, 2018 at 1:01 history edited j.c. CC BY-SA 3.0
update with new figure using McKay's computation
Apr 19, 2018 at 0:39 comment added Brendan McKay The probability that $C_n=n$ is $(1+o(1)) \sqrt{\pi/(4n)}\,e^{3/4}$. Proof as in my "answer".
Apr 18, 2018 at 0:52 history edited j.c. CC BY-SA 3.0
labeled graphs
Apr 18, 2018 at 0:44 history answered j.c. CC BY-SA 3.0