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May 19, 2021 at 15:04 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Apr 19, 2021 at 14:38 answer added Shah Faisal timeline score: 1
Apr 17, 2018 at 0:50 comment added user142700 @RobertBryant For the setting I had in mind, the curve had boundary in a Lagrangian submanifold. I was hoping to control the "size" of the curve" (with respect to some, say J-compatible, background metric). However, the question as posed is clearly too general, as you pointed out.
Apr 17, 2018 at 0:36 comment added Robert Bryant What do you mean by 'the diameter'? Are you fixing a metric on $\mathbb{R}^{2n}$? If so, is it assumed compatible with $J$ somehow? In general, I expect the answer is 'no' since, for the standard complex structure and metric on $\mathbb{R}^{2n}$ there is no bound on the diameter of holomorphic discs.
Apr 17, 2018 at 0:21 history asked user142700 CC BY-SA 3.0