Timeline for Extreme points of a convex set
Current License: CC BY-SA 3.0
15 events
when toggle format | what | by | license | comment | |
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Apr 14, 2018 at 2:09 | comment | added | Igor Rivin | @usul $m=n.$ hermitian matrices. | |
Apr 13, 2018 at 19:38 | answer | added | Dima Pasechnik | timeline score: 1 | |
Apr 13, 2018 at 18:29 | comment | added | usul | Sorry for ignorance, but what is the "space" here within which this is a convex set? The set of all linear functions from $\mathbb{C}^n \to \mathbb{C}^m$ for all $n,m \geq 1$? Or for fixed $n,m$? | |
Apr 13, 2018 at 18:17 | answer | added | Igor Rivin | timeline score: 1 | |
Apr 13, 2018 at 18:13 | comment | added | Igor Rivin | Standard terminology is "positive semidefinite" (PSD). | |
Apr 13, 2018 at 1:06 | history | edited | Mathbuff | CC BY-SA 3.0 |
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Apr 13, 2018 at 1:05 | comment | added | Mathbuff | @ Andreas. Yes. I copied and copied again. What is wrong in that? What he said is correct. | |
Apr 13, 2018 at 0:52 | comment | added | Andreas Blass | I think that, when editing, you copied the suggestion from @ChristianRemling incorrectly. The matrix $\binom{1\ 0}{0\ 0}$ is a non-zero extreme point. | |
Apr 13, 2018 at 0:31 | comment | added | Mathbuff | @ Christian. Edited. | |
Apr 13, 2018 at 0:30 | history | edited | Mathbuff | CC BY-SA 3.0 |
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Apr 13, 2018 at 0:26 | comment | added | Christian Remling | What could perhaps be true is that the extreme points have diag entries zero or one. | |
Apr 13, 2018 at 0:25 | comment | added | Christian Remling | This cannot be true because the set is the closed convex hull of its extreme points. Or in more elementary style, $0$ is certainly an extreme point. | |
Apr 13, 2018 at 0:06 | comment | added | Mathbuff | @Igor. Hermitian + all eigenvalues non-negative. | |
Apr 13, 2018 at 0:02 | comment | added | Igor Rivin | Non-negative definite = hermitian with some eigenvalues positive? Or do you mean something else? | |
Apr 13, 2018 at 0:00 | history | asked | Mathbuff | CC BY-SA 3.0 |