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Timeline for Extreme points of a convex set

Current License: CC BY-SA 3.0

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Apr 14, 2018 at 2:09 comment added Igor Rivin @usul $m=n.$ hermitian matrices.
Apr 13, 2018 at 19:38 answer added Dima Pasechnik timeline score: 1
Apr 13, 2018 at 18:29 comment added usul Sorry for ignorance, but what is the "space" here within which this is a convex set? The set of all linear functions from $\mathbb{C}^n \to \mathbb{C}^m$ for all $n,m \geq 1$? Or for fixed $n,m$?
Apr 13, 2018 at 18:17 answer added Igor Rivin timeline score: 1
Apr 13, 2018 at 18:13 comment added Igor Rivin Standard terminology is "positive semidefinite" (PSD).
Apr 13, 2018 at 1:06 history edited Mathbuff CC BY-SA 3.0
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Apr 13, 2018 at 1:05 comment added Mathbuff @ Andreas. Yes. I copied and copied again. What is wrong in that? What he said is correct.
Apr 13, 2018 at 0:52 comment added Andreas Blass I think that, when editing, you copied the suggestion from @ChristianRemling incorrectly. The matrix $\binom{1\ 0}{0\ 0}$ is a non-zero extreme point.
Apr 13, 2018 at 0:31 comment added Mathbuff @ Christian. Edited.
Apr 13, 2018 at 0:30 history edited Mathbuff CC BY-SA 3.0
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Apr 13, 2018 at 0:26 comment added Christian Remling What could perhaps be true is that the extreme points have diag entries zero or one.
Apr 13, 2018 at 0:25 comment added Christian Remling This cannot be true because the set is the closed convex hull of its extreme points. Or in more elementary style, $0$ is certainly an extreme point.
Apr 13, 2018 at 0:06 comment added Mathbuff @Igor. Hermitian + all eigenvalues non-negative.
Apr 13, 2018 at 0:02 comment added Igor Rivin Non-negative definite = hermitian with some eigenvalues positive? Or do you mean something else?
Apr 13, 2018 at 0:00 history asked Mathbuff CC BY-SA 3.0