Timeline for Proof of $L^1(\mathbb{R}) \ast f \neq L^1(\mathbb{R})$
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 11, 2018 at 0:58 | vote | accept | user95282 | ||
| Apr 11, 2018 at 0:58 | comment | added | user95282 | Yes, very nice. | |
| Apr 11, 2018 at 0:18 | comment | added | Iosif Pinelis | Indeed very simple. Note: $\hat f$ cannot have any zeros, since it must be a divisor of the function $t\mapsto e^{-t^2}$ (say). | |
| Apr 11, 2018 at 0:05 | history | answered | Gerald Edgar | CC BY-SA 3.0 |