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Apr 11, 2018 at 18:03 vote accept M.G.
Apr 10, 2018 at 15:03 comment added M.G. @JosephO'Rourke: thanks, I have seen your question and even posted an answer to it just now :-) However, the setting of your question is different in an essential way.
Apr 10, 2018 at 14:56 comment added Najib Idrissi @IgorRivin Why do you want the curves to be isotopic? The winding number of curves in the plane is a homotopy invariant. Moreover "isotopic", to my knowledge, refers to embedded submanifolds. Embedded curves in $\mathbb{R}^2$ are somewhat pointless (and the winding number is either zero or one).
Apr 10, 2018 at 14:43 comment added Joseph O'Rourke See also the earlier question, Generalization of winding number to higher dimensions.
Apr 10, 2018 at 13:31 history edited M.G.
per comments added soft-question tag
Apr 10, 2018 at 3:28 comment added Anthony Carapetis Well, I guess it depends what properties of the winding number you're trying to generalize; such a soft question perhaps should not be answered with a definite yes or no. To me the ambient isotopy class doesn't seem to be a good answer to this question, especially given its insensitivity to any "vantage point" $p$.
Apr 10, 2018 at 3:12 comment added Igor Rivin @AnthonyCarapetis being homotopic is irrelevant here - you want the curves to be isotopic, in which case your statement is false, as proved by the existence of the subject of "knot theory".
Apr 10, 2018 at 3:12 answer added Wlod AA timeline score: 7
Apr 10, 2018 at 3:01 comment added Anthony Carapetis yes, this makes more sense - see Piotr's answer re linking numbers.
Apr 10, 2018 at 2:58 comment added M.G. @AnthonyCarapetis: that's a really good point. At the same time it raises the question if one might be able to speak of a "winding number" of a curve with respect to some proper obstruction of codimension $2$ instead of a pt.
Apr 10, 2018 at 2:57 answer added Piotr Hajlasz timeline score: 13
Apr 10, 2018 at 2:46 comment added Anthony Carapetis Any two closed curves not touching $p$ are homotopic in $\mathbb R^3 \setminus \{p\},$ so I don't see how a useful definition is possible.
Apr 10, 2018 at 2:18 history asked M.G. CC BY-SA 3.0