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Apr 16, 2018 at 0:20 comment added Tim Campion What is $\bar F$? If it means algebraic closure, then it is not even functorial in $F$.
Apr 9, 2018 at 16:28 history edited YCor
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Apr 9, 2018 at 15:48 history edited Dubious CC BY-SA 3.0
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Apr 9, 2018 at 15:00 history asked Dubious CC BY-SA 3.0