Timeline for Must the set of lines through the origin on which a nonconstant entire function is bounded be finite?
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Nov 24, 2020 at 21:40 | history | edited | Michael Hardy | CC BY-SA 4.0 |
added 7 characters in body
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| May 27, 2017 at 8:32 | review | Close votes | |||
| May 27, 2017 at 10:31 | |||||
| May 27, 2017 at 8:13 | comment | added | Alexandre Eremenko | Your intuition is totally wrong: $e^z$ is bounded on all directions in the left half-plane. | |
| Sep 1, 2013 at 20:16 | history | edited | Andreas Rüdinger | CC BY-SA 3.0 |
Title improved according to the suggestion of Peter L Clark
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| Sep 1, 2013 at 20:14 | comment | added | Andreas Rüdinger | Many thanks for your comment. Actually, I was not happy with the formulation of my question, but couldn't find a better one (I'm not a native English speaker). I will change the question according to your suggestion. | |
| Sep 1, 2013 at 10:15 | comment | added | Pete L. Clark | This is a very interesting question -- the accepted answer startles and amazes me -- but I find the title hard to read and understand. (The way I read it, an answer would be: "Certainly yes -- e.g. $z^2$ is not bounded on any line through the origin.") Would(n't) something like "Must the set of lines through the origin on which a nonconstant entire function is bounded be finite?" be better? | |
| Jun 28, 2010 at 20:19 | vote | accept | Andreas Rüdinger | ||
| Jun 28, 2010 at 1:23 | history | edited | Gerry Myerson | CC BY-SA 2.5 |
corrected spelling
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| Jun 27, 2010 at 22:09 | answer | added | Andrey Rekalo | timeline score: 14 | |
| Jun 27, 2010 at 22:01 | answer | added | Jonas Meyer | timeline score: 60 | |
| Jun 27, 2010 at 21:41 | history | asked | Andreas Rüdinger | CC BY-SA 2.5 |