Timeline for How to show that the origin is not in the convex hull, in this problem?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 8, 2018 at 20:54 | comment | added | Malkoun | Well, I know it is true from another point of view... It would take some time to explain. Email me if you want. I will reply tomorrow. | |
| Apr 8, 2018 at 20:53 | comment | added | Iosif Pinelis | I think it is helpful, when one poses a conjecture, to also indicate reasons why the conjecture seems plausible. | |
| Apr 8, 2018 at 20:43 | comment | added | Malkoun | I checked my equations. Sorry, I had a mistake in them. I will edit my post... | |
| Apr 8, 2018 at 20:26 | comment | added | Iosif Pinelis | I have added a counterexample satisfying also the additional condition that the points $\mathbf x_i=(x_i,y_i,z_i)$ be nonzero. | |
| Apr 8, 2018 at 20:23 | history | edited | Iosif Pinelis | CC BY-SA 3.0 |
added 306 characters in body
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| Apr 8, 2018 at 20:15 | comment | added | Malkoun | I will also rederive the equations tomorrow to double check. | |
| Apr 8, 2018 at 20:13 | comment | added | Malkoun | oops I forgot to mention the $3$ points are in $\mathbb{R}^3 \setminus 0$. None of them can be at the origin. | |
| Apr 8, 2018 at 19:38 | comment | added | Malkoun | ok Thank you. It means I made a calculation mistake. I will correct my post tomorrow. Thank you though! | |
| Apr 8, 2018 at 19:36 | history | answered | Iosif Pinelis | CC BY-SA 3.0 |