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Apr 5, 2018 at 22:47 vote accept Shalom
Apr 5, 2018 at 3:55 comment added Gerry Myerson It is common to insist in this sort of problem that $a,b,c$ be relatively prime (as GH from MO does in his answer). Without that insistence, you can make as many solutions as you want. E.g., from $3^3+2^4=43$, we can get $a^3+b^4=c^5$ with $a=3\times43^8$, $b=2\times43^6$, $c=43^5$.
Apr 4, 2018 at 16:32 history edited GH from MO
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Apr 4, 2018 at 16:30 answer added GH from MO timeline score: 5
Apr 4, 2018 at 16:02 history asked Shalom CC BY-SA 3.0