Timeline for Is the function $g$ always injective where $g$ is obtained by lipschitz re-parametrization
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| Apr 1, 2018 at 9:53 | vote | accept | MathMan | ||
| Apr 1, 2018 at 5:54 | comment | added | Piotr Hajlasz | It is injective since it is the shortest one. My argument was by contradiction. | |
| Apr 1, 2018 at 5:52 | history | edited | Piotr Hajlasz | CC BY-SA 3.0 |
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| Apr 1, 2018 at 5:52 | comment | added | MathMan | okay. which means the answer to the problem posed is : $g$ may not be always injective but there exists one $g$ which is injective obtained by shortening the curve? | |
| Apr 1, 2018 at 5:49 | comment | added | Piotr Hajlasz | @MathMan I edited my answer to address your concern. | |
| Apr 1, 2018 at 5:48 | history | edited | Piotr Hajlasz | CC BY-SA 3.0 |
added 94 characters in body
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| Apr 1, 2018 at 5:40 | comment | added | MathMan | Thanks but the problem posed mentions $[0,1]$ as the domain. Aren't we altering the conditions of the problem by changing the domain? | |
| Apr 1, 2018 at 5:35 | history | answered | Piotr Hajlasz | CC BY-SA 3.0 |