Timeline for What is the intuition behind Almgren's frequency function?
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 12, 2019 at 13:51 | comment | added | Mizar | Nice answer! To expand slightly on the conclusion of this variational proof, note that $N_w(1)\ge N_u(1)=\gamma$ (again because $u$ minimizes the energy), so the condition that $N_w'(1)=0$ gives $0=\int_{\partial B_1}(|\nabla w|^2-2N_w(1)ww_\nu)-(n-2)\int_{B_1}|\nabla w|^2\le\int_{\partial B_1}(|\nabla w|^2-2\gamma ww_\nu)-(n-2)\int_{B_1}|\nabla w|^2$ (as $ww_\nu=\gamma w^2\ge 0$); the last quantity bounds from below $N_u'(1)$, so we get indeed $N_u'(1)\ge 0$. | |
| Apr 1, 2018 at 6:37 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 9 characters in body
|
| Apr 1, 2018 at 6:24 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 24 characters in body
|
| Mar 31, 2018 at 9:23 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 43 characters in body
|
| Mar 31, 2018 at 9:02 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 41 characters in body
|
| Mar 31, 2018 at 8:50 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 42 characters in body
|
| Mar 31, 2018 at 8:41 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 42 characters in body
|
| Mar 31, 2018 at 8:27 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 13 characters in body
|
| Mar 31, 2018 at 8:11 | history | edited | Connor Mooney | CC BY-SA 3.0 |
edited body
|
| Mar 31, 2018 at 8:03 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 183 characters in body
|
| Mar 31, 2018 at 7:54 | history | edited | Connor Mooney | CC BY-SA 3.0 |
added 22 characters in body
|
| Mar 31, 2018 at 7:48 | history | answered | Connor Mooney | CC BY-SA 3.0 |