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Mar 31, 2018 at 17:26 comment added S. carmeli This is not a mistake, in this book they consider algebraic geometry, and hence consider only \textbf{polynomial} (i.e. regular) functions. The complex conjugate of a polynomial function is anti-holomorphic and hence not a "function" in Gelfand-Kapranov-Zelevinski context.
Mar 30, 2018 at 22:44 comment added LSpice I'm sure it goes back much earlier than that, but a natural source for polynomial representations of $\mathrm{GL}(n)$ (the 1-dimensional ones being those @NeilStrickland describes) is Green - Polynomial representations of $\mathrm{GL}(n)$.
Mar 30, 2018 at 20:59 comment added Vincenzo Zaccaro @NeilStrickland many thanks for the helpfull remark. Can you give me a rference where I can find your claim? I know almost nothing about Rep. Theory.
Mar 30, 2018 at 20:31 comment added Adam P. Goucher A more pathological multiplicative function is $\chi(g) = \exp f(\log |\det g|)$, where $f$ is any solution to Cauchy's functional equation, and we further define $\chi(g) = 0$ whenever $g$ is singular.
Mar 30, 2018 at 20:15 comment added Neil Strickland The function $f$ is polynomial, and we can fix a generic $M$ and define $\chi(g)=f(gM)f(M)^{-1}$, so $\chi$ is also a polynomial function. Any character that is a polynomial function is a power of the determinant.
Mar 30, 2018 at 20:05 history asked Vincenzo Zaccaro CC BY-SA 3.0