Timeline for Is $\mathbb{Q}$ the continuous image of a Golomb-like space, or vice versa?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Jun 30, 2018 at 19:34 | history | edited | Taras Banakh | CC BY-SA 4.0 |
corrected a misprint in the title
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| Mar 30, 2018 at 19:06 | vote | accept | Dominic van der Zypen | ||
| Mar 30, 2018 at 17:23 | answer | added | YCor | timeline score: 6 | |
| Mar 30, 2018 at 12:33 | comment | added | YCor | Note: this topology is the topology induced by inclusion of $\omega$ (the natural numbers) into $\widehat{\mathbf{Z}}$ (the profinite completion of $\mathbf{Z}$). So this topology is actually homeomorphic to $\mathbf{Q}$, and is far from "Golomb-like", much more standard. (See math.stackexchange.com/questions/355779/… for this topological characterization) | |
| Mar 30, 2018 at 8:08 | history | edited | Dominic van der Zypen | CC BY-SA 3.0 |
edited title
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| Mar 30, 2018 at 7:18 | review | Close votes | |||
| Apr 2, 2018 at 17:36 | |||||
| Mar 30, 2018 at 6:48 | comment | added | Wojowu | $a\mapsto\lfloor a+\sqrt{2}\rfloor$ is a continuous surjection from $\mathbb Q$ to a discrete countable space. Feel free to take it from there. | |
| Mar 30, 2018 at 6:30 | comment | added | YCor | And this is not the definition of Golomb space: in the Golomb space $0$ is excluded, and $a,b$ are coprime. | |
| Mar 30, 2018 at 6:04 | history | asked | Dominic van der Zypen | CC BY-SA 3.0 |