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Apr 3, 2018 at 9:39 vote accept joro
Apr 2, 2018 at 13:31 comment added Lucia Yes (as $N\to \infty$).
Apr 2, 2018 at 8:47 comment added joro Thank you. Is $s^*(N,A)=A$ for $0 < A < 1$?
Mar 29, 2018 at 5:57 history answered Lucia CC BY-SA 3.0