Timeline for Bounding the derivative of a holomorphic function on a disk by its absolute value
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 27, 2018 at 6:42 | vote | accept | aglearner | ||
| Mar 26, 2018 at 18:22 | answer | added | Alexandre Eremenko | timeline score: 2 | |
| Mar 26, 2018 at 17:17 | comment | added | Christian Remling | If you rescale so that your big disk is $|z|<1$ and the small one is $|z|<1/2$, then this gives $c=4/3$. | |
| Mar 26, 2018 at 17:16 | comment | added | Christian Remling | The optimal inequality should be the one you get from the invariant form of the Schwarz lemma: en.wikipedia.org/wiki/Schwarz_lemma | |
| Mar 26, 2018 at 16:42 | comment | added | abx | Cauchy integral formula gives $\lvert f'(z)\rvert\leq 2$ (integrate over a circle centered at 0, of radius $2-\varepsilon $). This is certainly not optimal. | |
| Mar 26, 2018 at 16:10 | history | asked | aglearner | CC BY-SA 3.0 |