This is an intuitionistic modal logic consisting of the usual axioms for intuitionistic logic to which is adjoined a modal operator $\bigcirc$, obeying the following axioms (plus proof rule Modus Ponens and the rule "from $M \rightarrow N$$M \supset N$ infer $\bigcirc M \rightarrow \bigcirc N$$\bigcirc M \supset \bigcirc N$"):
The bimodal (S4, S4) logic into which we can translate lax logic has the usual propositional connectives together with two dual pairs of modalities $\Box_i, \Diamond_m, \Box_ m, \Diamond_ m$. A bimodal model is a Kripke structure $M=(W, R_m , R_i , V)$ where $W$ is a nonempty set, $R_i , R_m$ are binary relations on $W$, and $V$ is a map that assigns to every propositional constant $A$ a subset $V(A) \in W$. The modal axioms obeyed by the logic are the usual K,T and 4 axioms of S4, except that we have K, T and 4 axioms for both modals $\Box_i$ and $\Box_m$ (for example the K axioms splits into $Ki : \Box_i(M \rightarrow N) \rightarrow \Box_i M \rightarrow \Box_i N$$Ki : \Box_i(M \supset N) \supset \Box_i M \supset \Box_i N$ and $K_m : \Box_m(M \rightarrow N) \rightarrow \Box_m M \rightarrow \Box_m N)$$K_m : \Box_m(M \supset N) \supset \Box_m M \supset \Box_m N)$
$$(M \rightarrow N)^g =\Box_i(M^g \rightarrow N^g ) $$$$(M \supset N)^g =\Box_i(M^g \supset N^g ) $$