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May 11, 2020 at 15:40 comment added Todd Trimble Todd and Andreas: this is all interesting, and thanks, but mainly I was trying to clarify the intent of the question (and so my comment was directed to the OP).
May 11, 2020 at 14:38 comment added Andreas Blass The comment from @ToddEisworth is also what I would suggest, but you can shorten the hike a little (eliminate two negations) by taking the contrapositive: If a compact Hausdorff space can be covered by fewer than $\mathfrak c$ closed sets with empty interiors, then it has uncountably many pairwise disjoint open sets.
May 11, 2020 at 14:30 comment added Todd Eisworth @ToddTrimble: Not sure what sort of hikes you like, but MA is equivalent to the statement that Compact Hausdorff spaces without uncountable disjoint families of open subsets cannot be written as the union of fewer than continuum many closed nowhere dense sets.
May 11, 2020 at 12:37 comment added Todd Trimble By "quotable", I'm guessing you mean something you could easily say to a friend while on a hike.
May 11, 2020 at 12:26 history edited Jeremy Rickard CC BY-SA 4.0
corrected typos
May 11, 2020 at 12:19 history edited Joel David Hamkins
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Mar 25, 2018 at 16:58 answer added Joel David Hamkins timeline score: 8
Mar 25, 2018 at 16:54 comment added Michael Greinecker Section 13 of Consequences of Martin's axiom by David Fremlin should cover the most important equivalences.
Mar 25, 2018 at 16:31 history made wiki Post Made Community Wiki by Todd Trimble
Mar 25, 2018 at 15:29 review First posts
Mar 25, 2018 at 15:35
Mar 25, 2018 at 15:25 history asked Clarke CC BY-SA 3.0