Skip to main content
6 events
when toggle format what by license comment
Mar 26, 2018 at 18:01 vote accept Student
Mar 26, 2018 at 17:50 comment added Nate Eldredge @Student: You said "measure space" and that typically implies a positive measure. And the spectral theorem asserts the existence of a positive measure space such that blah blah blah, so for that application, only positive measures are relevant.
Mar 26, 2018 at 15:34 comment added Student I don't understand why we assume that $\mu$ is positive? So your idea in your comment here: mathoverflow.net/questions/294621/… works only if $\mu$ is positive. Do you agree with me? Thanks
Mar 24, 2018 at 17:01 comment added p4sch I have corrected my answer, too! My argument is the same as yours and I also added a proof of the fact that $\mu_{sf}$ is a measure.
Mar 24, 2018 at 16:21 history edited Nate Eldredge CC BY-SA 3.0
added 43 characters in body
Mar 24, 2018 at 16:16 history answered Nate Eldredge CC BY-SA 3.0