Timeline for About a property in a reflexive Banach space
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Mar 25, 2018 at 17:41 | review | Close votes | |||
| Apr 9, 2018 at 3:02 | |||||
| Mar 24, 2018 at 15:09 | history | edited | MSMalekan | CC BY-SA 3.0 |
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| Mar 24, 2018 at 14:16 | answer | added | Gerald Edgar | timeline score: 1 | |
| Mar 24, 2018 at 13:59 | comment | added | MSMalekan | @PietroMajer: You are right, I made it more clear. | |
| Mar 24, 2018 at 13:58 | history | edited | MSMalekan | CC BY-SA 3.0 |
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| Mar 24, 2018 at 10:39 | comment | added | Pietro Majer | Note that a sequence of linearly independent elements can possibly be a convergent sequence $x_n\to x$, which forces $y_n=Tx_n\to Tx$, so $(y_n)$ can't be arbitrary. Maybe you should restate more clearly the question. | |
| Mar 24, 2018 at 7:33 | history | edited | MSMalekan | CC BY-SA 3.0 |
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| Mar 24, 2018 at 7:25 | comment | added | MSMalekan | @NateEldredge: By your argument no such sequence $\{\phi_n\}$ exists. Thank you! | |
| Mar 24, 2018 at 7:18 | comment | added | MSMalekan | @NateEldredge I mean a bounded sequence. It is fixed now. | |
| Mar 24, 2018 at 7:14 | history | edited | MSMalekan | CC BY-SA 3.0 |
added 5 characters in body; edited title
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| Mar 24, 2018 at 5:52 | comment | added | Nate Eldredge | What does "normal element" mean? Does it mean $\|x_n\| = 1$? If so then the condition $\langle x_n, \phi_n \rangle = 1$ forces $\|\phi_n\| \ge 1$ and $\sum \|\phi_n\| = \infty$. | |
| Mar 24, 2018 at 5:52 | comment | added | user1688 | What is a normal element? | |
| Mar 24, 2018 at 5:41 | history | asked | MSMalekan | CC BY-SA 3.0 |