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Nov 5, 2020 at 4:20 comment added AlexArvanitakis @user539887 It looks like that's the same as the Dyson series (from HE theory)
Aug 1, 2019 at 10:57 comment added Pietro Majer For instance, the formula holds true if $A$ is a path of commuting operators: $[A(t),A(s)]=0$ for all $s,t$: then nothing changes w.r.to the scalar case.
Aug 27, 2018 at 14:58 comment added Phil Tosteson @Hans Physicists refer to the time ordered exponential: en.wikipedia.org/wiki/Ordered_exponential
May 4, 2018 at 8:20 comment added user539887 @Hans In contrast, the Magnus expansion is very complicated and may not converge except close to the initial time.
May 4, 2018 at 8:15 comment added user539887 @Hans The Peano-Baker series is, in my opinion, simple, and converges where it should. There is a nice paper by Baake and Schlägel The Peano-Baker series, Proceedings of the Steklov Institute of Mathematics 275 (1) (2011), 155-159 (the paper is behind a paywall on the Publisher's page, but the authors put a copy on ResearchGate (researchgate.net/publication/47702535_The_Peano-Baker_series)).
May 3, 2018 at 18:11 comment added Hans Is there a simple expression that is true?
Apr 27, 2018 at 23:26 comment added Michael I am holding this belief right now.
Mar 23, 2018 at 23:01 review Late answers
Mar 23, 2018 at 23:05
S Mar 23, 2018 at 22:45 history answered user539887 CC BY-SA 3.0
S Mar 23, 2018 at 22:45 history made wiki Post Made Community Wiki by user539887