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Mar 24, 2018 at 11:04 vote accept Pablo
Mar 23, 2018 at 17:20 comment added Derek Holt $CD = CD \cap CA = C(CD \cap A)$ so $D \cong CD/C = C(CD \cap A)/C \cong CD \cap A$.
Mar 23, 2018 at 14:29 comment added Pablo Why is the intersection in the second paragraph isomorphic to $D$? I think it is equivalent to $A$ containing $D$ but I do not see why this holds.
Mar 22, 2018 at 8:24 history answered Derek Holt CC BY-SA 3.0