Timeline for If you break a stick at two points chosen uniformly, the probability the three resulting sticks form a triangle is 1/4. Is there a nice proof of this?
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 6, 2023 at 8:13 | history | edited | Martin Sleziak | CC BY-SA 4.0 |
http -> https (the question was bumped anyway)
|
| S Jul 15, 2016 at 20:19 | history | suggested | Martin Sleziak | CC BY-SA 3.0 |
added links
|
| Jul 15, 2016 at 20:13 | review | Suggested edits | |||
| S Jul 15, 2016 at 20:19 | |||||
| Jun 4, 2011 at 15:40 | comment | added | Peter Shor | Both Kevin Costello's argument and mine can be adapted to give the $1-n/2^{n-1}$ answer in the general case. | |
| Jun 26, 2010 at 0:48 | comment | added | Michael Lugo | Mark, thanks! That's what I get for writing MathOverflow answers on an iPhone. (I was flipping through an old issue of the Monthly and wasn't near a computer.) | |
| Jun 26, 2010 at 0:47 | history | edited | Michael Lugo | CC BY-SA 2.5 |
completed
|
| Jun 25, 2010 at 20:00 | comment | added | Mark Meckes | There's something missing in your last sentence: $1-n/2^{n-1}$ is the probability of what event? | |
| Jun 25, 2010 at 19:34 | history | answered | Michael Lugo | CC BY-SA 2.5 |