Timeline for a category associated with an inverse semigroup
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 20, 2018 at 18:33 | comment | added | Benjamin Steinberg | BTW I'd be curious if you can find applications to flow equivalence beyond what we did. | |
| Mar 20, 2018 at 15:20 | vote | accept | David Hillman | ||
| Mar 16, 2018 at 11:24 | comment | added | Benjamin Steinberg | The translation is $aa^{-1}eb^{-1}b=e$ iff e is in $aS\cap Sb$ and if $e,f$ are as in the question then $e=eb^{-1}b$ and $f=bb^{-1}f$ and our multiplication rule is to remove one of the two $b$'s and multiply which gives $eb^{-1}bb^{-1}f=eb^{-1}f$. So we have exactly the same category except we oriented our arrows in opposite directions. | |
| Mar 15, 2018 at 23:16 | comment | added | David Hillman | That's fantastic, thanks! I'll have to dig in but am already pretty sure this is the same thing because I did the other day find that equivalent objects were given by the D relation. Also was surprised to see that this work was related to study of flow equivalence. The project that I'm working on is also related to flow equivalence! Will report back after I read your papers (which may take a while). | |
| Mar 15, 2018 at 7:41 | history | edited | YCor | CC BY-SA 3.0 |
added journal reference, formatted links
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| Mar 15, 2018 at 2:25 | history | edited | Benjamin Steinberg | CC BY-SA 3.0 |
added 234 characters in body
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| Mar 15, 2018 at 2:06 | history | edited | Benjamin Steinberg | CC BY-SA 3.0 |
added 52 characters in body
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| Mar 15, 2018 at 2:01 | history | answered | Benjamin Steinberg | CC BY-SA 3.0 |