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Mar 15, 2018 at 19:59 comment added Robert Israel Not quite. You could also have at least one of $Au=0$ and $B^T v = 0$ and at least one of $Cu=0$ and $D^T v=0$.
Mar 15, 2018 at 7:34 comment added baptiste Is it an equivalence?
Mar 14, 2018 at 20:37 review Low quality posts
Mar 14, 2018 at 20:38
Mar 14, 2018 at 20:21 history answered Robert Israel CC BY-SA 3.0