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Mar 22, 2018 at 18:14 vote accept Goldstern
Mar 14, 2018 at 13:45 history edited Goldstern CC BY-SA 3.0
formatting (spacing). Also removed "signature", as Peter probably did not know that the signature is added automatically
Mar 14, 2018 at 13:38 comment added Goldstern I am not interested in the case when $Q_0$ and $P_0$ are dominating in $P$; $Q$ respectively. But if $P\not= P_0$, one can extend $\varphi^-$ to all of $Q$ be mapping $Q\setminus Q_0$ into $P\setminus P_0$, and still keep the essential implication $\varphi^-(q) \le p \Rightarrow \dots$, as elements of $P\setminus P_0$ will not appear on the left side of the new (restricted) relation $\le$.
Mar 13, 2018 at 21:31 comment added Goldstern Hi, welcome to mathoverflow!
Mar 13, 2018 at 21:18 review First posts
Mar 13, 2018 at 21:52
Mar 13, 2018 at 21:18 history answered Peter Vojtas CC BY-SA 3.0