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Mar 10, 2018 at 20:23 comment added paul garrett The non-compact case is vastly more complicated, I think, for the reason(s) that essentially none of the "happy" control that we have in the compact case carries over to the non-compact case.
Mar 10, 2018 at 19:25 comment added Saal Hardali Eventually i'm really interested in the case where $G$ is non-compact real reductive. Do you know what happens in this case? At least whether one should expect the same kind of results?
Mar 10, 2018 at 18:29 history answered paul garrett CC BY-SA 3.0