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Semigroups admitting Commutative Groupcommutative group actions

Let $(S,*)$ be a semigroup admitting a distinguished element $0$ such that $z*s = s*z = z$, for all $s \in S$. Moreover, let $(\mathbb{G},\cdot)$ be a commutative group. Consider an action $$ \mathbb{G} \times S \to S, ~~~~~~~~~~~ (k,s) \mapsto k.s, $$ satisfying, for all $s,t \in S$, and $k,l \in \mathbb{G}$,

  1. $~~~ k.(l.s) = (k\cdot l).s$,

  2. $~~~ k.(s*t) = (k.s)*t = s*(k.t)$,

  3. $~~~~ 1_{\mathbb{K}}.s = s$$~~~~ 1_{\mathbb{G}}.s = s$,

  4. $~~~~ 0.s = z.$

Does such an object have a name, or is is easily seen to be equivalent to a standard structure? If such things are studied, what can one say about them?

Such a commutative semigroup admits an equivalence relation $$ s \simeq t, \text{ if there exists a } k \in \mathbb{G}, \text{ such that } s = k.t. $$ Does the quotient have $S/\simeq$$S\,/\!\simeq$ have a name. For example, might one call it the projectivization of $S$?

If $S$ is a monoid does anything extra interesting happen?

EDIT: Based on the comments of M. Sapir, the definition has been refined.

Semigroups admitting Commutative Group actions

Let $(S,*)$ be a semigroup admitting a distinguished element $0$ such that $z*s = s*z = z$, for all $s \in S$. Moreover, let $(\mathbb{G},\cdot)$ be a commutative group. Consider an action $$ \mathbb{G} \times S \to S, ~~~~~~~~~~~ (k,s) \mapsto k.s, $$ satisfying, for all $s,t \in S$, and $k,l \in \mathbb{G}$,

  1. $~~~ k.(l.s) = (k\cdot l).s$,

  2. $~~~ k.(s*t) = (k.s)*t = s*(k.t)$,

  3. $~~~~ 1_{\mathbb{K}}.s = s$,

  4. $~~~~ 0.s = z.$

Does such an object have a name, or is is easily seen to be equivalent to a standard structure? If such things are studied, what can one say about them?

Such a commutative semigroup admits an equivalence relation $$ s \simeq t, \text{ if there exists a } k \in \mathbb{G}, \text{ such that } s = k.t. $$ Does the quotient have $S/\simeq$ have a name. For example, might one call it the projectivization of $S$?

If $S$ is a monoid does anything extra interesting happen?

EDIT: Based on the comments of M. Sapir, the definition has been refined.

Semigroups admitting commutative group actions

Let $(S,*)$ be a semigroup admitting a distinguished element $0$ such that $z*s = s*z = z$, for all $s \in S$. Moreover, let $(\mathbb{G},\cdot)$ be a commutative group. Consider an action $$ \mathbb{G} \times S \to S, ~~~~~~~~~~~ (k,s) \mapsto k.s, $$ satisfying, for all $s,t \in S$, and $k,l \in \mathbb{G}$,

  1. $~~~ k.(l.s) = (k\cdot l).s$,

  2. $~~~ k.(s*t) = (k.s)*t = s*(k.t)$,

  3. $~~~~ 1_{\mathbb{G}}.s = s$,

  4. $~~~~ 0.s = z.$

Does such an object have a name, or is is easily seen to be equivalent to a standard structure? If such things are studied, what can one say about them?

Such a commutative semigroup admits an equivalence relation $$ s \simeq t, \text{ if there exists a } k \in \mathbb{G}, \text{ such that } s = k.t. $$ Does the quotient have $S\,/\!\simeq$ have a name. For example, might one call it the projectivization of $S$?

If $S$ is a monoid does anything extra interesting happen?

EDIT: Based on the comments of M. Sapir, the definition has been refined.

added 210 characters in body; edited title
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Semigroups admitting fieldCommutative Group actions

Let $(S,*)$ be a semigroup admitting a distinguished element $0$ such that $z*s = s*z = z$, andfor all $\mathbb{K}$$s \in S$. Moreover, let $(\mathbb{G},\cdot)$ be a fieldcommutative group. Consider an action $$ \mathbb{K} \times S \to S, ~~~~~~~~~~~ (k,s) \mapsto k.s, $$$$ \mathbb{G} \times S \to S, ~~~~~~~~~~~ (k,s) \mapsto k.s, $$ satisfying, for all $s,t \in S$, and $k,l \in \mathbb{K}$$k,l \in \mathbb{G}$,

  1. $~~~ k.(l.s) = (kl).s$$~~~ k.(l.s) = (k\cdot l).s$,

  2. $~~~ k.(s*t) = (k.s)*t = s*(k.t)$,

  3. $~~~~ 1_{\mathbb{K}}.s = s$.,

  4. $~~~~ 0.s = z.$

Does such an object have a name, or is is easily seen to be equivalent to a standard structure? If such things are studied, what can one say about them?

Such a commutative semigroup admits an equivalence relation $$ s \simeq t, \text{ if there exists a } \lambda \in \mathbb{C}, \text{ such that } s = \lambda t. $$$$ s \simeq t, \text{ if there exists a } k \in \mathbb{G}, \text{ such that } s = k.t. $$ Does the quotient have $S/\simeq$ have a name. For example, might one call it the projectivization of $S$?

If $S$ is a monoid does anything extra interesting happen?

EDIT: Based on the comments of M. Sapir, the definition has been refined.

Semigroups admitting field actions

Let $(S,*)$ be a semigroup, and $\mathbb{K}$ a field. Consider an action $$ \mathbb{K} \times S \to S, ~~~~~~~~~~~ (k,s) \mapsto k.s, $$ satisfying, for all $s,t \in S$, and $k,l \in \mathbb{K}$,

  1. $~~~ k.(l.s) = (kl).s$

  2. $~~~ k.(s*t) = (k.s)*t = s*(k.t)$,

  3. $~~~~ 1_{\mathbb{K}}.s = s$.

Does such an object have a name, or is is easily seen to be equivalent to a standard structure? If such things are studied, what can one say about them?

Such a commutative semigroup admits an equivalence relation $$ s \simeq t, \text{ if there exists a } \lambda \in \mathbb{C}, \text{ such that } s = \lambda t. $$ Does the quotient have $S/\simeq$ have a name. For example, might one call it the projectivization of $S$?

If $S$ is a monoid does anything extra interesting happen?

Semigroups admitting Commutative Group actions

Let $(S,*)$ be a semigroup admitting a distinguished element $0$ such that $z*s = s*z = z$, for all $s \in S$. Moreover, let $(\mathbb{G},\cdot)$ be a commutative group. Consider an action $$ \mathbb{G} \times S \to S, ~~~~~~~~~~~ (k,s) \mapsto k.s, $$ satisfying, for all $s,t \in S$, and $k,l \in \mathbb{G}$,

  1. $~~~ k.(l.s) = (k\cdot l).s$,

  2. $~~~ k.(s*t) = (k.s)*t = s*(k.t)$,

  3. $~~~~ 1_{\mathbb{K}}.s = s$,

  4. $~~~~ 0.s = z.$

Does such an object have a name, or is is easily seen to be equivalent to a standard structure? If such things are studied, what can one say about them?

Such a commutative semigroup admits an equivalence relation $$ s \simeq t, \text{ if there exists a } k \in \mathbb{G}, \text{ such that } s = k.t. $$ Does the quotient have $S/\simeq$ have a name. For example, might one call it the projectivization of $S$?

If $S$ is a monoid does anything extra interesting happen?

EDIT: Based on the comments of M. Sapir, the definition has been refined.

Removed deprecated (abstract-algebra) tag - see the tag info: https://mathoverflow.net/tags/abstract-algebra/info (if there are some other suitable tags, choose them instead.)
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Martin Sleziak
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