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Mar 31, 2018 at 15:02 history edited Martin Sleziak CC BY-SA 3.0
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Mar 31, 2018 at 14:41 history edited Paolo Leonetti CC BY-SA 3.0
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Mar 31, 2018 at 14:39 comment added Paolo Leonetti @MartinSleziak You are right in one point: I didn't check translations and the result depends on the choice of the bijection. On the other hand, I was referring the finite analogue, hence we'd need only $X \cap Y+k$ finite for each $k$. I don't know whether this can be fixed
Mar 31, 2018 at 14:34 comment added Martin Sleziak When you mention the construction of almost disjoint family from Albiac-Kalton, you mean that for any two sets from this family you have that $X\cap Y+k$ has zero density, right? Whether or not all these sets have positive upper density probably depends on the choice of the sequences and the choice of the bijection between $\mathbf N$ and $\mathbf Q$.
Mar 31, 2018 at 14:31 history edited Martin Sleziak CC BY-SA 3.0
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Mar 31, 2018 at 14:25 history edited Martin Sleziak CC BY-SA 3.0
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Mar 31, 2018 at 13:54 history edited Paolo Leonetti CC BY-SA 3.0
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Mar 9, 2018 at 21:28 history edited Paolo Leonetti CC BY-SA 3.0
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Mar 9, 2018 at 16:41 history edited Paolo Leonetti CC BY-SA 3.0
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Mar 9, 2018 at 13:48 vote accept Paolo Leonetti
Mar 9, 2018 at 13:19 answer added Mateusz Kwaśnicki timeline score: 6
Mar 9, 2018 at 13:08 history asked Paolo Leonetti CC BY-SA 3.0