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Mar 6, 2018 at 18:18 vote accept Jinglun Cai
Mar 4, 2018 at 14:36 comment added Joel David Hamkins Since this argument is a bit finicky, I wonder whether one might try something simpler. For example, suppose we just code the $\Sigma_2$-correct cardinals into the GCH pattern? Does this make $\Sigma_{n+1}$-correctness into mere $\Sigma_n$ correctness for all larger $n$? My idea is to drop down the complexity from the bottom, rather than from the top.
Mar 4, 2018 at 14:17 history answered Joel David Hamkins CC BY-SA 3.0