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Mar 5, 2018 at 17:17 comment added Ben Sprott Hi Tim, Yes, I what I meant by a factorization of the Giry Monad. I guess you have answered my question.
Mar 5, 2018 at 13:54 review Close votes
Mar 26, 2018 at 4:13
Mar 5, 2018 at 13:35 comment added Tim Campion What do you mean by "a factorization of the Giry monad"? Are you asking whether there is an adjunction $Pol^\to_\leftarrow Det-Stoch$ (where $Pol$ is the category of Polish spaces) whose induced monad on $Pol$ is the Giry monad? If that's what you mean, then the answer is obviously no: because $Det-Stoch$ has no noninvertible morphisms, any functor that factors through $Det-Stoch$ will send all morphisms to isomorphisms, and the Giry monad does not do this.
Mar 4, 2018 at 8:23 history edited Martin Sleziak CC BY-SA 3.0
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Mar 4, 2018 at 8:12 history edited Ben Sprott CC BY-SA 3.0
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Mar 4, 2018 at 8:04 history asked Ben Sprott CC BY-SA 3.0