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Ben Webster
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As far as I can tell your question is "can I reconstruct a polynomial from its roots." So, yes, you can consider the product $\prod_{\alpha} (x-\alpha(H))$ as a function on $\mathfrak{h}$ valued in polynomials. This is the same (by the definition of root) as the characteristic polynomial of the adjoint action by $H$ (on $\mathfrak{g}/\mathfrak{h}$; for all of $\mathfrak{g}$, you should multiply by $x^{\mathrm{dim}(\mathfrak{h})}$).

As far as I can tell your question is "can I reconstruct a polynomial from its roots." So, yes, you can consider the product $\prod_{\alpha} (x-\alpha(H))$ as a function on $\mathfrak{h}$ valued in polynomials. This is the same (by the definition of root) as the characteristic polynomial of the adjoint action by $H$.

As far as I can tell your question is "can I reconstruct a polynomial from its roots." So, yes, you can consider the product $\prod_{\alpha} (x-\alpha(H))$ as a function on $\mathfrak{h}$ valued in polynomials. This is the same (by the definition of root) as the characteristic polynomial of the adjoint action by $H$ (on $\mathfrak{g}/\mathfrak{h}$; for all of $\mathfrak{g}$, you should multiply by $x^{\mathrm{dim}(\mathfrak{h})}$).

Source Link
Ben Webster
  • 44.7k
  • 12
  • 126
  • 260

As far as I can tell your question is "can I reconstruct a polynomial from its roots." So, yes, you can consider the product $\prod_{\alpha} (x-\alpha(H))$ as a function on $\mathfrak{h}$ valued in polynomials. This is the same (by the definition of root) as the characteristic polynomial of the adjoint action by $H$.