Timeline for Finitely generated $K_0$ of $C^*$-algebras
Current License: CC BY-SA 3.0
16 events
when toggle format | what | by | license | comment | |
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Mar 10, 2018 at 17:33 | answer | added | Caleb Eckhardt | timeline score: 3 | |
Mar 8, 2018 at 19:37 | answer | added | hänsel | timeline score: 0 | |
Mar 8, 2018 at 0:56 | comment | added | Ruy | When a dense subalgebra is invariant under analytic functional calculus, its K-theory is isomorphic to that of the ambient algebra, so I suggest you check whether that property holds on the examples you are interested. | |
Mar 4, 2018 at 0:59 | history | edited | David Handelman | CC BY-SA 3.0 |
TeX; punctuation; clarification
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Mar 4, 2018 at 0:23 | history | edited | Doc Matrix | CC BY-SA 3.0 |
Claification of notation
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Mar 3, 2018 at 21:57 | comment | added | LSpice | It's certainly your right to rollback edits to the question, but why insist on $C*$ in place of $C^*$, and why the '---'s? | |
Mar 3, 2018 at 21:34 | comment | added | David Handelman | Of course what I meant by maximum and minimum norms were the full and regular representation norms, but that occurred to me just more than five minutes after ... | |
Mar 3, 2018 at 21:28 | comment | added | David Handelman | How about the following. Take $A_0 = B_0 = {\bf C}G$ (the group algebra on the group $G$), and suppose that $G$ is not amenable. Then the maximum and minimum norms yield non-isomorphic C*-algebras $A$ and $B$ respectively. I am not that familiar with the horde of results in this area, but there presumably are examples where one of them has merely ${\bf Z}$ as its $K_0$, and the other one has lots of projection-equivalence classes, enough to guarantee non-finite generation. | |
Mar 3, 2018 at 19:17 | history | edited | Doc Matrix | CC BY-SA 3.0 |
Clarification of assumptions stated in the question.
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Mar 3, 2018 at 18:58 | history | edited | YCor |
edited tags; edited tags
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S Mar 3, 2018 at 18:29 | history | edited | LSpice | CC BY-SA 3.0 |
latex and english edits
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S Mar 3, 2018 at 18:29 | history | suggested | Amir Sagiv | CC BY-SA 3.0 |
latex and english edits
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Mar 3, 2018 at 18:28 | comment | added | LSpice | If $A_0$ and $B_0$ are not necessarily isomorphic as $*$-algebras, then in what category are they assumed isomorphic? | |
Mar 3, 2018 at 18:11 | review | Suggested edits | |||
S Mar 3, 2018 at 18:29 | |||||
Mar 3, 2018 at 18:07 | review | First posts | |||
Mar 3, 2018 at 18:12 | |||||
Mar 3, 2018 at 18:07 | history | asked | Doc Matrix | CC BY-SA 3.0 |