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Mar 3, 2018 at 15:10 comment added Jon Pridham Of course, for any homotopy type $X$ you have an associated $\infty$-stack given by hypersheafifiying the constant presheaf $X$. $K(G,1)$ would then usually be called $BG$. [Etale homotopy types go in the opposite direction, producing homotopy types from stacks.]
Mar 3, 2018 at 11:04 comment added Jon Pridham The issue with schematic homotopy types comes entirely from π1; for instance the pro-reductive completion of an abelian group is Spec of its character ring (usually huge). Smaller relative completions are more manageable; completion relative to 1 just gives Sullivan's rational homotopy types, regarded as stacks by passing to the associated cosimplicial algebra.
Mar 3, 2018 at 6:41 comment added Tim Porter Perhaps you should indicate what you mean by 'an arbitrary homotopy type' and also how you would like `'interesting' to be interpreted. Pro-finite homotopy theory is the obvious place to look.
Mar 3, 2018 at 2:07 comment added user40276 ... that have the $G_F$ as a $\pi^1$ and cohomology on $Z/n$ agreeing with Galois cohomology. Btw, I don't know how étale homotopy theory should be on the pro-étale site instead of the étale.
Mar 3, 2018 at 2:07 comment added user40276 I'm aware of only one way of attaching homotopy types to algebraic objects. You can take the étale pro homotopy type a derived higher stack arxiv.org/abs/1506.07155 . Étale homotopy types were first defined by Artin-Mazur and refined by Frieddlander. Later Hoyois gave this better description. I don't know though what would be the correct site for derived schemes/stack. In the case of $K (G, 1)$, any field with absolute Galois group G will do the job. There's also Scholze-Kucharczyk paper arxiv.org/pdf/1609.04717.pdf constructing a space functorially for fields of char $0$ ...
Mar 2, 2018 at 23:53 history edited David Handelman CC BY-SA 3.0
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Mar 2, 2018 at 23:53
Mar 2, 2018 at 23:43 history asked Patrick Elliott CC BY-SA 3.0