Timeline for Orbits of the function f(x)=2x (mod 1)
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Mar 19, 2018 at 15:40 | comment | added | YCor | Anyway it's a bit weird to melt in the definition both the iterated inverse images (backwards orbit) and the iterated images (forward orbit). The orbit should then include all the inverse images of the forward images? For $1/2$ it does not matter but for $1/3$ one gets $1/3\to 2/3\leftarrow 5/6$, and $5/6$ is neither in the forwards nor backwards orbit of $1/3$. | |
| Mar 19, 2018 at 15:35 | comment | added | YCor | @AnthonyQuas No. It's with $m\in\mathbf{Z}$. So it includes all iterated inverse images, that is, $\mathbf{Z}[1/2]/\mathbf{Z}$ (or intersection with $[0,1[$ for those who prefer fundamental domains). | |
| Mar 8, 2018 at 3:03 | review | Close votes | |||
| Mar 8, 2018 at 23:58 | |||||
| S Mar 3, 2018 at 0:04 | history | suggested | Ali Taghavi |
I add a tag.
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| Mar 2, 2018 at 22:13 | review | Suggested edits | |||
| S Mar 3, 2018 at 0:04 | |||||
| Mar 2, 2018 at 18:57 | history | edited | Miguel Barata | CC BY-SA 3.0 |
edited body
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| Mar 2, 2018 at 18:55 | vote | accept | Miguel Barata | ||
| Mar 2, 2018 at 18:31 | answer | added | Aaron Meyerowitz | timeline score: 6 | |
| Mar 2, 2018 at 18:10 | review | Close votes | |||
| Mar 3, 2018 at 0:12 | |||||
| Mar 2, 2018 at 17:24 | comment | added | Anthony Quas | $\mathbb Z[\frac 12]$ means the dyadic rationals (all rationals with denominator a power of 2). This is (presumably) not what you mean (but rather $\frac 12\mathbb Z$). | |
| Mar 2, 2018 at 16:49 | review | First posts | |||
| Mar 2, 2018 at 16:50 | |||||
| Mar 2, 2018 at 16:48 | history | asked | Miguel Barata | CC BY-SA 3.0 |