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Apr 2, 2018 at 20:48 comment added Ben McKay @YosemiteSam: the classic refence is Atiyah, Complex analytic connections in fibre bundles, Transactions of the Amer. Math. Soc. 85 (1957), 181-207. MR 19:172c.
Apr 2, 2018 at 19:55 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Mar 3, 2018 at 18:17 answer added Donu Arapura timeline score: 1
Mar 3, 2018 at 17:59 comment added Marion @YosemiteSam I don't think this statement is quite true. Analytically a connection will define a curvature and that is directly related to the $c_1$, the first Chern class. For a line bundle $c_1$ is far from trivial while indeed $c_2=0$.
Mar 3, 2018 at 17:57 comment added Yosemite Sam @abx do you have a reference / proof for the fact you mention? (i.e. a vector bundle with connection has trivial chern classes) I'd never heard of it and I'm very interested.
Mar 3, 2018 at 12:56 history edited Marion CC BY-SA 3.0
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Mar 3, 2018 at 11:45 comment added Marion What does this notation mean (the $d$ part)? But I do not understand why a vector bundle with connection has trivial Chern classes? Do you mean fixed?
Mar 3, 2018 at 11:39 comment added abx You are indeed far off. A vector bundle with a connection has trivial Chern classes. For $X=\mathbb{P}^2$, the only line bundle with a connection is $(\mathcal{O}_{\mathbb{P}^2},d)$.
Feb 28, 2018 at 20:44 history asked Marion CC BY-SA 3.0