Skip to main content
7 events
when toggle format what by license comment
Feb 16, 2021 at 15:09 history edited gmvh CC BY-SA 4.0
Added DOI link for cited paper, added tag
Oct 28, 2018 at 20:59 vote accept Amir Sagiv
Aug 15, 2018 at 12:34 answer added Iddo Hanniel timeline score: 3
Aug 8, 2018 at 5:27 comment added Amir Sagiv @IddoHanniel yes, it is still possible that there's a better $L^2$ bound, either a better rate or at least a better constant $C$. If there isn't, where's the counter-example?
Aug 7, 2018 at 16:02 comment added Iddo Hanniel If I understand correctly you want a bound on $\|f(x)-s(x)\|_2 = \sqrt{\int_a^b (f(x)-s(x))^2 dx}$. Since you have a bound $\left | f(x)-s(x) \right | \leq C h^4 = M$ (from Hall & Meyer), then $\sqrt{\int_a^b (f(x)-s(x))^2 dx} \leq \sqrt{M^2(b-a)} = C h^4 \sqrt{(b-a)} $. Doesn't that give you a sufficient $L_2$ bound? or am I missing something?
Feb 27, 2018 at 5:09 history edited Amir Sagiv CC BY-SA 3.0
writing more concise
Feb 26, 2018 at 21:51 history asked Amir Sagiv CC BY-SA 3.0