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Feb 26, 2018 at 17:49 history closed Andreas Blass
Paul Siegel
Ben McKay
Peter Heinig
Olivier
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Feb 26, 2018 at 16:49 comment added LSpice @PaulSiegel, of course I guess your comment means "the map $H \mapsto H^*$ is uniquely determined by the fact that it is Zariski continuous and …".
Feb 26, 2018 at 16:35 history edited David Watson CC BY-SA 3.0
Added quick definition of the adjugate matrix.
Feb 26, 2018 at 16:30 comment added David Watson @PaulSiegel I agree. It's a reference for the proof that both my formulas follow from this property that I'm looking for.
Feb 26, 2018 at 16:05 review Close votes
Feb 26, 2018 at 17:54
Feb 26, 2018 at 15:57 comment added Paul Siegel $H^*$ is uniquely determined by the identity $H H^* = H^* H = \det(H) I$. I think both of your formulas follow from that (together with the usual properties of determinants).
Feb 26, 2018 at 15:45 review First posts
Feb 26, 2018 at 15:46
Feb 26, 2018 at 15:43 history asked David Watson CC BY-SA 3.0