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Feb 27, 2018 at 15:39 comment added Alexandre Eremenko @Bazin: Yes, in this example zero is the unique analytic function which satisfies your equation. The solution is always unique..
Feb 27, 2018 at 14:27 comment added Bazin Take $a=1/2$, $f=0$, so that the equation reads $2x z'=z$. Multiplying both sides by $z$, calling $y=z^2$, you get $xy'=y$ and thus $y=\alpha x$. If $z$ is analytic, $:alpha\not=0$,and $\zeta= \alpha^{-1/2}z$, you found an analytic function $\zeta$ such that $\zeta^2=x$, which is not possible. Thus $z=0$.
Feb 27, 2018 at 12:40 vote accept Alex Gavrilov
Feb 26, 2018 at 23:12 history edited Alexandre Eremenko CC BY-SA 3.0
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Feb 26, 2018 at 15:31 history edited Alexandre Eremenko CC BY-SA 3.0
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Feb 26, 2018 at 14:22 history answered Alexandre Eremenko CC BY-SA 3.0