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Mar 6, 2018 at 15:12 comment added Najib Idrissi Yes, of course. Apply the theorem to $H_{op}$, which is the same as $H$ but with product $a \cdot_{op} b = ba$ and coproduct $\Delta_{op} = \tau \Delta$, where $\tau : H^{\otimes 2} \to H^{\otimes 2}$ exchanges the two factors.
Feb 22, 2018 at 23:09 history edited YCor
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Feb 22, 2018 at 20:38 history asked Jianrong Li CC BY-SA 3.0