Timeline for Do pseudo-differential operators form a sheaf of algebras?
Current License: CC BY-SA 3.0
12 events
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Jul 4, 2018 at 13:08 | vote | accept | Saal Hardali | ||
Jul 4, 2018 at 13:08 | vote | accept | Saal Hardali | ||
Jul 4, 2018 at 13:08 | |||||
Feb 20, 2018 at 14:56 | answer | added | Dmitri Pavlov | timeline score: 5 | |
Feb 20, 2018 at 11:26 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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Feb 20, 2018 at 8:32 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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Feb 19, 2018 at 22:33 | answer | added | Peter Michor | timeline score: 6 | |
Feb 19, 2018 at 22:26 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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Feb 19, 2018 at 22:24 | comment | added | Saal Hardali | @paulgarrett Aha! So my suspicions were well founded! If it is indeed true that associativity fails it is rather unfortunate that this fact is glossed over so much in the literature. I hope some expert will eventually find this post and clear this up. | |
Feb 19, 2018 at 22:20 | comment | added | paul garrett | My amateur appraisal on this is that there is definitely an issue about composition, especially if you want composition to be associative, if we can't take a quotient by smoothing operators. I don't have an example off-hand, but this is surely vaguely similar to the old chestnut that $(1*\delta')*H\not=1*(\delta'*H)$ where $H$ is the Heaviside function. The problem is that not-compact-support distributions (for example) don't form a reasonable convolution algebra, certainly not compatibly with a purported action on nice functions... and so on. | |
Feb 19, 2018 at 21:27 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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Feb 19, 2018 at 21:20 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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Feb 19, 2018 at 21:14 | history | asked | Saal Hardali | CC BY-SA 3.0 |