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user64494
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Mathematica answers

Sum[Binomial[a, k - i]*Binomial[b + i, i], {i, 0, k},Assumptions -> a >= k | b > 0]

$$\binom{a}{k} \, _2F_1(b+1,-k;a-k+1;-1) $$ Addition. Maple performs

sum(binomial(a, k-i)*binomial(b+i, i), i = 0 .. k)assuming a>=k,b>0

$${a\choose k}{\mbox{$_2$F$_1$}(-k,b+1;\,a-k+1;\,-1)} $$ I think both answers are equivalent.

Mathematica answers

Sum[Binomial[a, k - i]*Binomial[b + i, i], {i, 0, k},Assumptions -> a >= k | b > 0]

$$\binom{a}{k} \, _2F_1(b+1,-k;a-k+1;-1) $$

Mathematica answers

Sum[Binomial[a, k - i]*Binomial[b + i, i], {i, 0, k},Assumptions -> a >= k | b > 0]

$$\binom{a}{k} \, _2F_1(b+1,-k;a-k+1;-1) $$ Addition. Maple performs

sum(binomial(a, k-i)*binomial(b+i, i), i = 0 .. k)assuming a>=k,b>0

$${a\choose k}{\mbox{$_2$F$_1$}(-k,b+1;\,a-k+1;\,-1)} $$ I think both answers are equivalent.

Source Link
user64494
  • 3.5k
  • 14
  • 22

Mathematica answers

Sum[Binomial[a, k - i]*Binomial[b + i, i], {i, 0, k},Assumptions -> a >= k | b > 0]

$$\binom{a}{k} \, _2F_1(b+1,-k;a-k+1;-1) $$