Timeline for Is every endomorphism of the sheaf of holomorphic functions on a disk a differential operator?
Current License: CC BY-SA 3.0
20 events
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| Feb 19, 2018 at 21:24 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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| Feb 19, 2018 at 17:35 | vote | accept | Saal Hardali | ||
| Feb 19, 2018 at 14:14 | comment | added | Saal Hardali | @SimonWadsley That's cool! I would be really grateful If you could change your answer, so that understanding its content wouldn't require exiting the site. | |
| Feb 19, 2018 at 14:12 | comment | added | Simon Wadsley | where continuity means as in your edit. | |
| Feb 19, 2018 at 14:12 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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| Feb 19, 2018 at 14:11 | comment | added | Simon Wadsley | The paper I mention below shows that there is no counter-example in the continuous case. I don't know what happens without continuity. | |
| Feb 19, 2018 at 14:11 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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| Feb 19, 2018 at 13:49 | comment | added | Saal Hardali | @SimonWadsley For starters i'm willing to ignore continuity entirely. Maybe a counterexample will convince me not to. | |
| Feb 19, 2018 at 13:00 | answer | added | Simon Wadsley | timeline score: 4 | |
| Feb 19, 2018 at 12:59 | comment | added | Rafael Mrden | Oh, I see I was wrong, thanks. Of course, $\phi$ need not a priori be extendable to continuous functions. | |
| Feb 19, 2018 at 12:56 | comment | added | Simon Wadsley | Do you have any continuity constraint on sheaf endomorphisms? | |
| Feb 19, 2018 at 12:10 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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| Feb 19, 2018 at 12:07 | comment | added | Saal Hardali | @RafaelMrđen I'm not sure how Peetre's theorem can be applied here, $\mathcal{O}_D$ can't be in any obvious sense a sheaf of smooth sections of a vector bundle as smooth functions don't act on it by multiplication. | |
| Feb 19, 2018 at 12:03 | comment | added | Qfwfq | @Rafael Mrđen: what about $\bar{\partial}$ ? | |
| Feb 19, 2018 at 11:55 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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| Feb 19, 2018 at 11:23 | comment | added | Rafael Mrden | Such an operator cannot be support non-increasing, by Peetre's theorem ( en.wikipedia.org/wiki/Peetre_theorem ). | |
| Feb 19, 2018 at 8:58 | history | edited | Saal Hardali |
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| Feb 19, 2018 at 8:44 | history | edited | Saal Hardali | CC BY-SA 3.0 |
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| Feb 19, 2018 at 8:39 | history | edited | Saal Hardali |
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| Feb 19, 2018 at 8:33 | history | asked | Saal Hardali | CC BY-SA 3.0 |