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May 17, 2019 at 17:08 comment added LSpice How do you single out a (family of) measure on this space, which does not carry any obvious group action, as 'Haar measure'? Do you just mean the measure for which $$\int_{\operatorname{SL}_3(\mathbb R)} f(x)\mathrm dx = \int_{\operatorname{SL}_3(\mathbb Z)\backslash{\operatorname{SL}_3(\mathbb R)}/{\operatorname{SO}_3(\mathbb R)}} \Bigl(\int_{\operatorname{SL}_3(\mathbb Z)x{\operatorname{SO}_3(\mathbb R)}} f(y)\mathrm dy\Bigr)\mathrm dx?$$
Feb 20, 2018 at 6:59 history edited user120980 CC BY-SA 3.0
edited body
Feb 20, 2018 at 6:58 comment added user120980 It's edited, thanks for noticing and explaining.
Feb 20, 2018 at 6:52 vote accept user120980
Feb 19, 2018 at 13:42 comment added YCor In general for double coset spaces $\Gamma\backslash G/K$ ($G$ unimodular, $K$ compact, $\Gamma$ discrete) the main step is to describe a $G$-invariant Radon measure on $G/K$, and then modding out by $\Gamma$ yields the given space ($G/K$ already known the local form of the measure). The main difficulty is not to describe the measure, but rather describe a fundamental domain. There exists a large literature on this, starting with Siegel. See Peter's answer.
Feb 19, 2018 at 13:35 comment added YCor It's: "Iwasawa"
Feb 19, 2018 at 11:39 answer added Peter Humphries timeline score: 14
Feb 19, 2018 at 11:18 history edited Peter Humphries CC BY-SA 3.0
added 98 characters in body; edited tags; edited title
Feb 19, 2018 at 7:06 review First posts
Feb 19, 2018 at 7:12
Feb 19, 2018 at 7:05 history asked user120980 CC BY-SA 3.0