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Apr 24 at 18:43 comment added valle Related: math.stackexchange.com/questions/4904882/… (I posted the question before realizing this was here)
Nov 4, 2019 at 6:03 vote accept Manfred Weis
Feb 16, 2018 at 20:06 answer added Peter Heinig timeline score: 7
Feb 16, 2018 at 19:22 history edited Peter Heinig CC BY-SA 3.0
Grammatical corrections (comma, capitalizations). Abbreviation set in normal font, not math-mode.
Feb 16, 2018 at 19:13 history edited Manfred Weis CC BY-SA 3.0
replaced the former 0-Stochastik projection matrix with Zero Line-Sum matrix
Feb 16, 2018 at 6:33 comment added Manfred Weis @GerryMyerson if "line" covers "row" and "column" then that is good alternative to my doubly "0-Stochastic".
Feb 16, 2018 at 6:13 comment added Gerry Myerson How about "zero line-sum matrices"?
Feb 16, 2018 at 6:00 comment added Manfred Weis @GerryMyerson I would be happy about a better name for those matrices (I just learned that projection matrix has a special meaning. What "my" matrices can do, is to remove constants that have been added to all elements of a column (when multiplying from the left) or to all elments of a row (when multiplying from the right), so I am tempted to call them "cyclic difference matrix" or maybe there is also the possibility to damp or enhance certain frequencies per row or column and thus an attribute relating to "Fourier" would be more appropriate.
Feb 15, 2018 at 21:54 comment added Gerry Myerson So these "doubly stochastic projection matrices" are neither doubly stochastic nor projection matrices.
Feb 15, 2018 at 15:11 history edited Manfred Weis CC BY-SA 3.0
clarified the loose meaning of projection
Feb 15, 2018 at 13:05 comment added Jochen Glueck @Manfred Weis: Let us consider the matrix $M =\begin{pmatrix} 1 & -1 \\ -1 &1 \end{pmatrix}$ The columns and rows sum up to $0$, but $M^2 \not= M$. What projection associated to $M$ do you have in mind?
Feb 15, 2018 at 13:01 comment added Manfred Weis @JochenGlueck as the rank of those matrices can't be full, there must be a kernel that is mapped 0 and I am convinced that in that case one has a projection matrix.
Feb 15, 2018 at 12:57 comment added Manfred Weis @FedericoPoloni my only restriction would be, that the entries are between -1 and +1; rational entries with small denominators and matrices with high rank would be preferrable to me.
Feb 15, 2018 at 12:36 comment added Federico Poloni Do you have any constraint on the value or sign of their elements?
Feb 15, 2018 at 12:34 comment added Jochen Glueck Could you please specify what you mean by "of the projections they define"? There are matrices whose rows and columns all sum up to $0$, but which are not projecctions.
Feb 15, 2018 at 12:19 history asked Manfred Weis CC BY-SA 3.0